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代码整理器

2010年8月06日 23:55 | Comments(15) | Category:C语言 | Tags:

/*Neat Code v0.1 author:star date:2010
没有经过优化和维护,一次写成版本。为了方便地整理排版乱的代码。
*/
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void NeatSpace(FILE *fin, FILE *fout);		//格式化空格字符
int  NeatType(FILE *fin, FILE *fout);		//格式化缩进
void Putlevel(FILE *out, int lv);			//输出缩进

int main(int argc, char *argv[])
{
	FILE *fin, *fout;
	char buf[255]= "t_";
	int  ErrorCode;

	if(1 == argc)
	{
		printf("Neat Code v0.1 -- star\n\n");
		printf("整理成Star喜欢的代码样式。\n");		
		printf("Usage:\nNeatCode source [destination]\n\n");
		printf(" source         指定要整理的文件。\n");		
		printf(" [destination]  可生成的目标文件。\n\n");	
		printf("如果没有输入目标文件,将会生成默认的。\n");					
	}
	else
		if(2 == argc)
		{
			if(!(fin = fopen(argv[1], "r")))
			{
				printf("错误001 - 无法打开%s文件。", argv[1]);
				return EXIT_FAILURE;
			}
			fout = fopen("~TEMP.NTC", "w");
			NeatSpace(fin, fout);
			fclose(fin);fclose(fout);
			fin = fopen("~TEMP.NTC", "r");
			strncpy(buf+2, argv[1], 253);
			if(!(fout = fopen(buf, "w")))
			{
				printf("错误002 - 创建%s文件失败。", buf);
				return EXIT_FAILURE;
			}
			ErrorCode = NeatType(fin, fout);
			fclose(fin);fclose(fout);
			system("del ~TEMP.NTC");
			if(ErrorCode) printf("错误005 - 所格式化的代码不标准 代码%d。", ErrorCode);
			else printf("成功执行!");
		}
		else
			if(3 == argc)
			{
				if(!(fin = fopen(argv[1], "r")))
				{
					printf("错误001 - 无法打开%s文件。", argv[1]);
					return EXIT_FAILURE;
				}
				fout = fopen("~TEMP.NTC", "w");
				NeatSpace(fin, fout);
				fclose(fin);fclose(fout);
				fin = fopen("~TEMP.NTC", "r");
				if(!(fout = fopen(argv[2], "w")))
				{
					printf("错误003 - 创建新的%s文件失败。", argv[2]);
					return EXIT_FAILURE; 
				}
				ErrorCode = NeatType(fin, fout);
				fclose(fin);fclose(fout);
				system("del ~TEMP.NTC");
				if(ErrorCode) printf("错误005 - 所格式化的代码不标准 代码%d。", ErrorCode);
				else printf("成功执行!");
			}else
			{
				printf("错误004 - 无效的命令。");
			}

			return EXIT_SUCCESS;
}

void NeatSpace(FILE *fin, FILE *fout)
{
	char ch = fgetc(fin);
	short cflag = 1;

	while(!feof(fin))
	{
		if(ch == '/' &&  fputc(ch, fout) && (ch=fgetc(fin)))
		{
			if(ch == '/' && fputc(ch, fout))
				while((ch=fgetc(fin)) != '\n') fputc(ch, fout);
			else if(ch == '*' && fputc(ch, fout))
				while((ch=fgetc(fin)) != '/') fputc(ch, fout);
		}
		if(ch == '\n' && (cflag = 1) && fputc(ch, fout))
		{
			ch = fgetc(fin);
			while(!feof(fin) && ch == '\n' || ch == ' ' || ch == '\t') ch = fgetc(fin);
			continue;
		}
		if(ch == ' ' || ch == '\t')
		{
			if(cflag == 0) fputc(ch, fout);
			while(ch == ' ' || ch == '\t') ch = fgetc(fin);
			continue;
		}
		else
		{
			if (ch != '{') cflag = 0;
			do{fputc(ch, fout);ch = fgetc(fin);}
			while(ch != '\n' && ch != ' ' && ch != '\t');
		}
	}
}

int NeatType(FILE *fin, FILE *fout)
{
	char ch = fgetc(fin);
	short IsTop = 1;
	signed int level = 0;

	if(ch == '\n') ch = fgetc(fin);
	while(!feof(fin))
	{
		while(ch != '\n' && ch != '{' && ch != '}')
		{
			IsTop = 0;
			fputc(ch, fout);
			ch = fgetc(fin);
		}
		if(ch == '\n' && (IsTop = 1))
		{
			fputc(ch, fout);
			ch = fgetc(fin);
			if(ch != '}')
				Putlevel(fout, level);
		}else
			if(ch == '{')
			{
				++level;
				if(!IsTop) fputc('\n', fout);				
				while(ch = fgetc(fin))
					if(ch == ' ' || ch == '\t');
					else if(ch == '\n') {fputc('{', fout);break;}
					else
					{
						Putlevel(fout, level-1);
						fputc('{', fout);
						fputc('\n', fout);
						break;
					}
				Putlevel(fout, level);				
			}else
				if(ch == '}')
				{
					--level;
					if(!IsTop) fputc('\n', fout);
					Putlevel(fout, level);
					fputc('}', fout);
					ch = fgetc(fin);
				}		
	}
	return level;
}

void Putlevel(FILE *out, int lv)
{
	if(lv > 0)
		while(lv--) fputc('\t', out);
}

上次不小心删了,再发一次吧。

求一个数是第几个排列数

2010年8月06日 00:47 | Comments(81) | Category:C语言 | Tags:

根据康托展开公式:$$C = \left\sum_{i=1}^{n}a_i(i-1)!\right$$

a[i]为第i个数比后面的都小的个数。

#include <stdio.h>
#include <string.h>
int FAC[10] = {1,1,2,6,24,120,720,5040,40320,362880};
int CantorExp(char *s, int n)
{
	int i, j, t, num = 0;
	for(i = 0; i < n; ++i)
	{
		t = 0;
		for(j = i+1; j < n; ++j)
			if(s[j] < s[i])
				++t;
		num += FAC[n-i-1]*t;
	}
	return num+1;
}
int main(int argc, char *argv[])
{
	char s[] = "1324";	//输入一个排列数的字符串序列 
	printf("%d", CantorExp(s, strlen(s)));
	return 0;
}

 

中文汉字转拼音首字母

2010年8月05日 03:43 | Comments(1) | Category:C++ | Tags:

/*ConvertToPY v0.1 author:star date:2010-02-25 */
#include <iostream> 
#include <string> 

using namespace std; 
static char convert(wchar_t n);
static bool In(wchar_t start, wchar_t end, wchar_t code);

int main(int argc, char* argv[]) 
{
	string sChinese = "取得拼音的首字母"; //   输入的字符串
	char chr[3]; 
	wchar_t wchr = 0; 
	char* buff = new char[sChinese.length()/2]; 
 
	memset(buff, 0, sizeof(char)*sChinese.length()/2+1); 
	for (int i = 0, j = 0; i < (sChinese.length()/2); ++i) 
	{   
		memset(chr, 0, sizeof(chr)); 
		chr[0]  = sChinese[j++]; 
		chr[1]  = sChinese[j++]; 
		chr[2]  = '\0'; 
		wchr    = 0; 
		wchr    = (chr[0] & 0xff) << (1<<3); 
		wchr   |= (chr[1] & 0xff); 
		buff[i] = convert(wchr); 
	} 
	cout << "结果 :[" << buff << "]" << endl; 
	return 0; 
} 
char convert(wchar_t n) 
{  
	if (In(0xB0A1,0xB0C4,n)) return 'A'; 
	if (In(0XB0C5,0XB2C0,n)) return 'B'; 
	if (In(0xB2C1,0xB4ED,n)) return 'C'; 
	if (In(0xB4EE,0xB6E9,n)) return 'D'; 
	if (In(0xB6EA,0xB7A1,n)) return 'E'; 
	if (In(0xB7A2,0xB8c0,n)) return 'F'; 
	if (In(0xB8C1,0xB9FD,n)) return 'G'; 
	if (In(0xB9FE,0xBBF6,n)) return 'H'; 
	if (In(0xBBF7,0xBFA5,n)) return 'J'; 
	if (In(0xBFA6,0xC0AB,n)) return 'K'; 
	if (In(0xC0AC,0xC2E7,n)) return 'L'; 
	if (In(0xC2E8,0xC4C2,n)) return 'M'; 
	if (In(0xC4C3,0xC5B5,n)) return 'N'; 
	if (In(0xC5B6,0xC5BD,n)) return 'O'; 
	if (In(0xC5BE,0xC6D9,n)) return 'P'; 
	if (In(0xC6DA,0xC8BA,n)) return 'Q'; 
	if (In(0xC8BB,0xC8F5,n)) return 'R'; 
	if (In(0xC8F6,0xCBF0,n)) return 'S'; 
	if (In(0xCBFA,0xCDD9,n)) return 'T'; 
	if (In(0xCDDA,0xCEF3,n)) return 'W'; 
	if (In(0xCEF4,0xD188,n)) return 'X'; 
	if (In(0xD1B9,0xD4D0,n)) return 'Y'; 
	if (In(0xD4D1,0xD7F9,n)) return 'Z'; 
	return 0; 
} 
inline bool In(wchar_t start, wchar_t end, wchar_t code) 
{  
	if (code >= start && code <= end) 
		return true; 
	return false; 
}